-
-
25
-
0链接:https://pan.baidu.com/s/1D66n68hnIM5AB9lSqELtdw 提取码:kacm
-
6
-
1
-
0有一个量是x1=x1'+1,这个'怎么打,试了(x1)'显示不对
-
0请问这个代码哪里不对 为什么显示格式错误 model: max=72*x+64*y; x+y<=40; 10*x+8*y<=480; 3*x<=100; x>=0; y>=0; end
-
0model: sets: cities/city1..city22/:city,arrival,introduce_time; links(cities,cities):dist,route; endsets data: dist=@ole('C:/math/2/dist.xlsx','get_time'); introduce_time=@ole('C:/math/2/dist.xlsx','introduce_time'); enddata max=@sum(cities(i):arrival(i)); arrival(1)=1; n=@sum(cities(i):arrival(i)); @for(links(i, j) : @bin(route(i, j))); 》@for(cities(m):arrival(m)=@sum(cities(m):route(m,o))+@sum(cities(m):route(o,m))); @for(cities(i) : @sum(cities(j) : route(j,i)) <1); @for(cities(i) : @sum(cities(j) : route(i,j)) <1); @sum(links(i,j):dist(i,j)*route(i,j
-
6
-
0我其他部分都能正常运行,只有“!同一条生产线上的模具尺寸之差不能大于10”这句下面那条语句会被报错。而且注意到我的DATA段中的那条输出语句使用的是与出错语句同样的内容,也就是说同样一个量,可以正常输出,但是无法在程序过程中进行约束 MODEL: SETS: route:……; line:…… ; mould:……, sizetest; ……; output(mould,line):solution; output2(route,line):solution2; ……; ENDSETS DATA: glove,line,mould,sizetest,……=@ole('D:\……\APS.xls'); ……; @text() = @writefor (line(L) | @su
-
5
-
1
-
132商用请购买正版 楼下网盘,自取到的请留下言,不做伸手党
-
2建立了一个模型但不知道怎么代码化 max=1200(x11+x12+x13)+800(x21+x22+x33)+700(x31+x23+x33); 9*x11+8*x21+6*x31<=2200;9*x12+8*x22+6*x32<=3200; 9*x13+8*x23+6*x33<=1200; 11*x11+6*x21+8*x31<=4200; 11*x12+6*x22+8*x32<=5400; 11*x13+6*x23+8*x33<=1200; x11+x12+x13<=650; x21+x22+x23<=1100; x31+x32+x33<=900; 0.5775<(9*x11+8*x21+6*x31)/(9*x12+8*x22+6*x32)<=0.7975; 0.315<(9*x13+8*x23+6*x33)/(9*x12+8*x22+6*x32)<=0.435; 1.61<(9*x11+8*x21+6*x31)/(9*x13+8*x23+6*x33)<=2.05;
-
0
-
0
-
1or和and的区别在哪里
-
1
-
0
-
0
-
0这是程序 model: sets: supply/1..3/:s; demand/1..4/:d; quota1/1..2/:u1,c1,p1; quota2/1..2/:u2,c2,p2; quota3/1..2/:u3,c3,p3; link0(supply,demand):t; link1(supply,demand,quota1):x1; link2(supply,demand,quota2):x2; link3(supply,demand,quota3):x3; ear1(demand,quota1):v1,n1; ear2(demand,quota2):v2,n2; ear3(demand,quota1):v3,n3; endsets data: s=5000,5000,6000; t=35,25,20 30,50,28 45,30,56 30,40,30; u1=5,8; u2=6,5; u3=9,7; c1=200,120; c2=240,160; c3=160,100; p1=10,8; p2=10,8; p3=10,8; v1=400,500 300,400 200,300 800,800; v2=300,300 1000,100 800,500 100,100; v3=300,200 100,600 400,400 100,400; n1=15
-
1求方程: a/d=sin(x/2)*sin(y/2+z)/cos(x/2-y/2) b/d=sin(x/2)*cos(y/2+z)/sin(x/2-y/2) (c/d)^2=(a/d+b/d)^2+1-2(a/d+b/d)*cosz 其中a b x y是赋值变
-
0
-
2
-
1
-
1
-
1
-
0
-
0
-
0
-
14
-
1