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1楼 Name: Command Line Calculator Version 1.0.1 Copyright: akuma@tds Author: akuma@tds Date: 06/01/05 03:00 Description: This is a free software distributed under The free beer license version 1.02 */ #include <stdio.h> #include <stdlib.h> #include <errno.h> #include <limits.h> #include <string.h> int isNumber(const char *buf); void display_license(void); void display_copyright(void); void display_help(void); int process_cmd(char *cmd); void get_cmd(char *buf, int buf_size); const char *delimiters = " \n\t,;"; const char *fs_d = "%ld"; const char *s_prompt = "# "; const char *s_acc_mode_prompt = " + "; const char *s_final_result = "\n[result] = %ld\n"; const char *s_result = "[result] = %ld, [operand] = %ld\n"; const char *s_clear = "[result] and [operand] had been set to zero\n"; const char *s_acc_mode = "[+] accumulation mode activated, enter zero to exit\n"; const char *s_acc_exit = "[-] exit accumulation mode\n"; const char *s_trc_mode = "[+] trace mode activated\n"; const char *s_trc_exit = "[-] trace mode off\n"; const char *s_warning_2_num = "[warning] more than one numbers entered, set operand equal to the first one\n"; const char *s_warning_2_cmd = "[warning] entered more than one command, only the first one will be used\n"; const char *s_warning_mt_2_cmd = "[warning] too much command, every entry except first two will be discarded\n"; const char *s_warning_ofr_num = "[warning] the number is out of range, reset operand to zero\n"; const char *s_error_bad_num = "[error] unrecognizable number entered\n"; const char *s_error_unknown = "[error] unknown command\n"; const char *s_error_dbz = "[error] %ld cannot be devided by zero\n"; const char *s_copyright = "Command Line Calculator 1.0.1 - copyright © 2005 akuma@tds\n" "- This is a free software distributed under The free beer license version 1.02\n" "- enter h for help, L for license information, q to exit\n" "\n"; /* 下面继续 */ |
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2楼 "FREE BEER LICENSE VERSION 1.02\n" "The free beer license is a license to give free software to you and free\n" "beer (in)to the author(s).\n" "Your rights are :\n" "0. You can use this piece of software in anyway you like.\n" "1. You can redistribute this piece of software in source form or in\n" " compiled form.\n" "2. You can alter the source to your needs and redistribute the altered\n" " source in source form or in compiled form.\n" "However :\n" "0. This program is provided without warranty of any kind. So, if it\n" " breaks anything, for example itself, it is up to you.\n" "1. If you redistribute this piece of software, you are not allowed to\n" " charge money for this piece of software itself.\n" "2. If you redistribute this pieces of software in binary form, you must\n" " supply the source code as well.\n" "3. If you redistribute this software, modified or not, you must\n" " redistribute it under this license and you must include the name of\n" " the original author(s) and you must point out where the original\n" " source can be obtained.\n" "4. If you use this piece of software frequently, and you think it is\n" " worth a couple of dollars, you are not allowed to send the author\n" " anything else than beer or means that provide facilities to get beer\n" " into the author(s) (i.e. openers, glasses).\n"; const char *s_helpmsg = "enter: # [operator] [number] -------- (1)\n" " or # [number] [operator] -------- (2)\n" " or # [command¦operator¦number] -------- (3)\n" " [command]\n" " Q¦q (3) : exit this program\n" " H¦h (3) : display this message\n" " L¦l (3) : display the license information\n" " S¦s (3) : enter accumulation mode\n" " T¦t (3) : toggle trace display\n" " C¦c (3) : reset the value of result and operand\n" " [operator]\n" " ? (3) : display the value of result and operand\n" " + (1¦2) : add [number] to the result\n" " (3) : add operand to the result\n" " - (1) : result - [number]\n" " (2) : [number] - result\n" " * (1¦2) : multiply the result by [number]\n" " (3) : multiply the result by operand\n" " / (1) : result / [number]\n" " (2) : [number] / result\n" " (3) : result / operand\n" " = (1¦2) : assign [number] to he result\n" " (3) : make result equal to operand\n" " [number] : set operand = [number], prefix 0x for Hex, 0 for Oct\n"; /* 下面继续 */ |
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3楼 /* Stupid M$ compiler doesn't allow me to define a char array */ /* with a const int. So I have to use macro here for M$ C*/ #define max_buffer 81 #else const int max_buffer = 81; #endif int isNumber(const char *buf) { int i = 0; if (('-' == buf[0] ¦¦ '+' == buf[0])) i++; if ('\0' == buf[i]) { return 0; } else if ('0' == buf[i] && ('X' == buf[i+1]) ¦¦ ('x' == buf[i+1])) { i += 2; while (buf[i]) if (!isxdigit(buf[i++])) return 0; } else if ('0' == buf[i]) { while (buf[i]) { if (!isdigit(buf[i]) ¦¦ buf[i] > '7') return 0; i++; } } else { while (buf[i]) if (!isdigit(buf[i++])) return 0; } return 1; } long read_value(const char *buf) { long ret = 0; ret = strtol(buf, NULL, 0); if (ERANGE == errno && ((LONG_MAX == ret) ¦¦ (LONG_MIN == ret))) { printf(s_warning_ofr_num); ret = 0; } return ret; } void display_license(void) { printf(s_license); } /* 下面继续 */ |
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4楼 { printf(s_copyright); } void display_help(void) { printf(s_helpmsg); } int process_cmd(char *cmd) { static long result = 0; static long operand = 0; static int trace_mode = 0; char buf[max_buffer]; char * temp_p; char command = ' '; int post = 0; if (NULL == (temp_p = strtok(cmd, delimiters))) return 1; if (isNumber(temp_p)) { operand = read_value(temp_p); if (NULL == (temp_p = strtok(NULL, delimiters))) command = ' '; else if (!isNumber(temp_p)) { post = 1; command = temp_p[0]; if ('\0' != temp_p[1] && !isdigit(temp_p[0])) command = '\0'; } else { printf(s_warning_2_num); } } else { command = temp_p[0]; if ('\0' != temp_p[1] && !isdigit(temp_p[0])) command = '\0'; post = 0; if (NULL != (temp_p = strtok(NULL, delimiters))) if (isNumber(temp_p)) operand = read_value(temp_p); else printf(s_warning_2_cmd); } if (NULL != (temp_p = strtok(NULL, delimiters))) printf(s_warning_mt_2_cmd); /* 下面继续 */ |
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5楼 case ' ': break; case 'h': case 'H': display_help(); break; case 'l': case 'L': display_license(); break; case 't': case 'T': trace_mode = !trace_mode; printf((trace_mode) ? s_trc_mode : s_trc_exit); break; case '?': printf(s_result, result, operand); break; case 'q': case 'Q': printf(s_final_result, result); return 0; case 'c': case 'C': result = operand = 0; printf(s_clear); break; case 's': case 'S': printf(s_acc_mode); do { if (trace_mode) printf(fs_d, result); printf(s_acc_mode_prompt); fgets(buf, max_buffer - 1, stdin); operand = read_value(buf); result += operand; } while (operand); printf(s_acc_exit); break; case '+': result += operand; break; case '-': if (post) result = operand - result; else result -= operand; break; case '*': result *= operand; break; case '/': if (post) result = operand / result; else if (operand == 0) printf(s_error_dbz, result); else result /= operand; break; case '=': result = operand; break; default: if (isdigit(command)) printf(s_error_bad_num); else printf(s_error_unknown); break; } /* 下面继续 */ |
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6楼 switch (command) { case '?': case 'h': case 'H': case 'l': case 'L': break; default: printf(s_result, result, operand); } return 1; } void get_cmd(char *buf, int buf_size) { printf(s_prompt); fgets(buf, buf_size - 1, stdin); } int main(int argc, char *argv[]) { char input_buffer[max_buffer]; display_copyright(); get_cmd(input_buffer, max_buffer); while (process_cmd(input_buffer)) get_cmd(input_buffer, max_buffer); return 0; } |
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7楼 14 回复：求救—用c语言编一个分数计算器的程序 编写一个简单的计算器，允许键入表达格式是 ：number operator,该程序应能识别+ - * / s q 其中s通知程序键入累加器一个数，q表示结束。(我只想要这些） 作者： 219.238.129.* 2005-1-5 22:24 回复此发言 /*******************************************/ 我早就写好了,只是不想帮人做功课,现在才贴,哈哈 |
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| 220.169.61.* |
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| 61.178.63.* |
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| 202.206.40.* |
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| 59.72.4.* |
18楼 send + more ----------- money 这个题吗?各个字母不同,求各个字母代表的数字 |
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| 59.44.126.* |
19楼 请问上句话是何意识？ |
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| 222.244.119.* |
20楼 能不能搞个能运行的啊 |
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21楼 哦!!对了.有愿意的..给我发信息..是baidu的 |
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| 211.167.89.* |
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| 222.83.136.* |
26楼 AKUMA 听着怎么象日本名呀... |
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| 220.181.48.* |
27楼 就比如78，先按下7，然后再按8，那么7怎么移到左边一位的啊？？ |
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| 61.191.30.* |
28楼 我没看明白 前2天 我们老师也叫我们写个命令行。计算器。。 要就 输入：路径\文件名 X（0-9） +（-*/） Y（0-9） 我小写了下 int main(int argc, char *argv[]) {int i,j; clrscr(); printf("please input :lujing\file X（0-9） +（-*/） Y（0-9）") if(argc!=3) printf("error"); i=*argv[1]-'\0'; j=*argv[3]-'\0'; switch(*argv[2]) case'+':printf("%d",i+j);break; case'-':printf("%d",i-j);break; case'*';printf("%d",i*j);break; case'/':printf("%d",i/j);break; default: printf("error!"); } 刚学 不知道对不对 也没运行 就发上来了 |
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| 61.191.30.* |
29楼 {int i,j; clrscr(); printf("please input :lujing\file x（0-9） +（-*/） y（0-9）"); if(argc!=6) printf("error"); i=*argv[2]-'\0'; j=*argv[6]-'\0'; switch(*argv[4]) {case'+':printf("%d",i+j);break; case'-':printf("%d",i-j);break; case'*';printf("%d",i*j);break; case'/':printf("%d",i/j);break; default: printf("error!"); } } 改正了下 还是不对 高手指点一点 |
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| 58.248.27.* |
30楼 |
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